20x^2-7x-6=(5x+2)

Solution for 20x^2-7x-6=(5x+2) equation:

20x^2-7x-6=(5x+2)

We move all terms to the left:

20x^2-7x-6-((5x+2))=0


We calculate terms in parentheses: -((5x+2)), so:

(5x+2)

We get rid of parentheses

5x+2

Back to the equation:

-(5x+2)


We get rid of parentheses

20x^2-7x-5x-2-6=0

We add all the numbers together, and all the variables

20x^2-12x-8=0

a = 20; b = -12; c = -8;
Δ = b2-4ac
Δ = -122-4·20·(-8)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-28}{2*20}=\frac{-16}{40}
=-2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+28}{2*20}=\frac{40}{40}
=1
$